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  • Plain Explanation

    “Both this sentence is false and this sentence is false or is this sentence is false.”

    The statement above systematizes the liar’s revenge sentence to the hypothetical solution to the liar sentence. Filling out the corresponding truth tables would state that if the revenge statement were true, it would be either false or equal to the liar sentence; if the revenge sentence were false, the revenge statement would be true; and if the revenge sentence were equal to the liars sentence, it would be true. The liar sentence was established to be not true in the initial characterization of the liar sentence.

    In the case of incompleteness, filling out the corresponding truth table shows that the follow-up “revenge statement” to the traditional antimony of the liar would set the revenge statement equal to true if it were incomplete, true if it were false, and either incomplete or false if it were true. That incompleteness differed from truth was established in the solution to the traditional liar paradox in the first step.

  • On the Formula

    I think the Boolean algebra formula for the paradox might be right – perhaps it is redundant, but I think it is perhaps sufficient to code the paradox as a logic circuit.

  • Regarding the Translation of the Formalism to Formal Symbolic Logic

    It is easy to imagine that a statement could be evaluated as true or false in formal symbolic logic. Therefore, the statement evaluated as true or false, in formal symbolic logic, could be itself. From there, it is easy to translate the whole formalism to formal symbolic logic – “both a statement that evaluates itself as false and a statement that evaluates iself as a statement that evaluates itself as false or false”.

    Of course, this translation doesn’t rebut answers such as Tarski’s, that language can’t define its own truth predicate, for example. But, classical logic per se ineluctably incurs a paradox.

  • Slightly Clearer Phrasing

    Both:

    Subpoint A: that subpoint A is false

    and

    Subpoint B: that subpoint B is equal to subpoint A or false

    Update 6/12/2026 – Explanation

  • Modern Phrasing

    I’m using the following phrasing for the natural language formalism:

    Both this sentence is false and this sentence is false or is this sentence is false

    Update 6/12/2026 – Explanation

  • Formal Symbolic Language Translation


    A translation from the natural language formalism into a formal symbolic language is easily and readily imaginable, and can be asserted.

  • Natural Language Phrasing

    I am incapable of evaluating the Boolean algebra phrasing of the formalism for rectitude. In lieu, a natural language phrasing of the paradox would proceed as follows:

    This sentence is false or is “this sentence is false”.

    Update – I went back to my original phrasing, as of 6/11/2026

  • Correcting a Major Error

    I just noticed that my formula is redundant. It should read:

    Assume Boolean algebra:

    x=((x=0) ∨ (x=(x=(x=0))))

    It corresponds to the sentence “This sentence is false or ‘this sentence is false’ “

    Update – I went back to my original phrasing, as of 6/11/2026

  • Updated Formalism

    Assume boolean algebra.

    ((x=(x=0)) ∧ (x=((x=0) ∨ (x=(x=(x=0))))))

    Update 6/13/2026 –

    Explanation: this is an attempt to formalize the liar’s sentence + liar’s revenge sentence in boolean algebra; I am far from certain I did so correctly.

  • Modern Interpretation

    I’ve come to the decision to categorize boolean algebra as an assumption, and to defend assuming boolean algebra on its own merits. I think assuming binary logic is probably defensible. So, schematically, I would assume boolean algebra, defend that assumption, and use the assumption of boolean algebra to derive a paradox. Obviously there’s work that needs to be done defending my assumption, but on the other hand, I think that that work can be done. I think that the idea that “logic is true” is sound.

    That being said, my hypothesis raises the possibility of three-value proofs.